How do I compare lambda function objects in C++?

How do I compare lambda function objects in C++?

In C++, lambda functions are not directly comparable because they are unique types. You can compare them by their behavior or by using std::function.

Can you show me an example of comparing two lambda functions?

Sure! You can use std::function to wrap your lambdas and then compare their results. Here's a simple example:

#include <iostream>
#include <functional>

int main() {
    auto lambda1 = [](int x) { return x + 1; };
    auto lambda2 = [](int x) { return x + 1; };

    std::function<int(int)> func1 = lambda1;
    std::function<int(int)> func2 = lambda2;

    std::cout << (func1(5) == func2(5) ? "Equal" : "Not Equal") << std::endl;
}

What if the lambdas have different implementations?

If the lambdas have different implementations, you can compare their outputs for the same input. However, you won't be able to directly compare the lambda objects themselves.

Is there a way to store lambda functions in a container?

Yes, you can store lambda functions in a container like std::vector by using std::function as the type. This allows you to store different lambdas in the same container.