What is the behavior of the C++ compiler with function overloading?

Can you explain how the C++ compiler handles function overloading?

Sure! In C++, function overloading allows multiple functions to have the same name but different parameters. The compiler differentiates them based on the number and type of arguments.

What happens if I overload a function with the same parameter types?

If you overload a function with the same parameter types, the compiler will throw an error because it cannot distinguish between the functions. Each overloaded function must have a unique signature.

Can you give me an example of function overloading?

Of course! For example, you can have void print(int a) and void print(double b). The compiler knows which function to call based on the argument type you provide.

Are there any limitations to function overloading?

Yes, function overloading cannot be done based solely on return type. The parameter list must differ in type or number for the compiler to distinguish between them.