Can you explain how capturing variables works in C++ lambda expressions?
Sure! In C++, lambda expressions can capture variables from their surrounding scope. This can be done by value or by reference.
What’s the difference between capturing by value and by reference?
Capturing by value means a copy of the variable is made, while capturing by reference means the lambda uses the original variable. Changes to the original variable will reflect in the lambda if captured by reference.
Can you give me an example of each?
Absolutely! For capturing by value: auto lambda = [x]() { return x + 1; };
For capturing by reference: auto lambda = [&x]() { x += 1; };
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What happens if the captured variable goes out of scope?
If the captured variable goes out of scope, accessing it in the lambda will lead to undefined behavior, especially if captured by reference.
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