How do I merge two sorted linked lists in C++?
You can merge two sorted linked lists by iterating through both lists and comparing their nodes. Would you like a code example?
Yes, please provide a code example.
Here's a simple implementation:
struct Node {
int data;
Node* next;
};
Node* mergeSortedLists(Node* l1, Node* l2) {
if (!l1) return l2;
if (!l2) return l1;
Node* head = nullptr;
if (l1->data < l2->data) {
head = l1;
l1 = l1->next;
} else {
head = l2;
l2 = l2->next;
}
Node* current = head;
while (l1 && l2) {
if (l1->data < l2->data) {
current->next = l1;
l1 = l1->next;
} else {
current->next = l2;
l2 = l2->next;
}
current = current->next;
}
current->next = (l1) ? l1 : l2;
return head;
}
This function merges two sorted linked lists into one sorted list.
What is the time complexity of this algorithm?
The time complexity of this algorithm is O(n + m), where n and m are the lengths of the two linked lists. This is because we traverse each list once.
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