Can you explain how exceptions are handled with std::async in C++?
Sure! When using std::async, if an exception is thrown in the asynchronous task, it will be captured and can be retrieved using the future object.
What happens if I don't call get() on the future?
If you don't call get() on the future, the exception will not be rethrown, and it will lead to a call to std::terminate when the future is destroyed.
Is there a way to check if an exception occurred without calling get()?
Yes, you can use the wait_for() or wait() methods to check if the task is done, but you still need to call get() to access the exception.
Can you give an example of handling exceptions with std::async?
Certainly! Here's a simple example:
#include <future>
#include <iostream>
#include <stdexcept>
int riskyFunction() {
throw std::runtime_error("Error occurred!");
}
int main() {
auto future = std::async(std::launch::async, riskyFunction);
try {
future.get();
} catch (const std::exception& e) {
std::cout << "Caught exception: " << e.what() << std::endl;
}
}
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