What are the differences between constexpr and macros in C++14?

What are the differences between constexpr and macros in C++14?

In C++14, constexpr allows for compile-time evaluation of functions and variables, while macros are preprocessor directives.

Can you give an example of how to use constexpr?

Sure! Here's a simple example:

constexpr int square(int x) {
    return x * x;
}

int main() {
    constexpr int result = square(5);
}

How do macros differ in terms of type safety?

Macros lack type safety since they are replaced by the preprocessor before compilation, while constexpr respects types.

Are there any performance differences between using constexpr and macros?

Yes, constexpr can lead to better optimization by the compiler, while macros can introduce overhead and potential errors.