How can I use lambda expressions in C++ threads?

How can I use lambda expressions in C++ threads?

You can use lambda expressions to create inline functions that can be executed in threads. Here's a simple example:

#include <iostream>
#include <thread>

int main() {
    std::thread t([]() {
        std::cout << "Hello from the thread!" << std::endl;
    });
    t.join();
    return 0;
}

This code creates a thread that runs a lambda function.

What are the benefits of using lambda expressions in threads?

Using lambda expressions in threads allows for cleaner and more concise code. It helps avoid the need for separate function definitions, making it easier to pass parameters and maintain context.

Can I capture variables in a lambda expression?

Yes, you can capture variables in a lambda expression by value or by reference. For example:

int x = 10;
std::thread t([x]() {
    std::cout << "Value of x: " << x << std::endl;
});

This captures x by value.

Are there any limitations to using lambda expressions in threads?

One limitation is that if you capture variables by reference, they must remain in scope for the duration of the thread's execution. Otherwise, you may encounter undefined behavior.