Can I use destructuring with default values in JavaScript?
Yes, you can use destructuring with default values in JavaScript. For example, if you have an object like { a: 1 }
, you can destructure it with a default value for b
like this: const { a, b = 2 } = obj;
.
What happens if the property is undefined?
If the property is undefined, the default value will be used. In the previous example, if obj
is { a: 1, b: undefined }
, then b
will still be 2
.
Can I use this with arrays too?
Absolutely! You can use destructuring with default values for arrays as well. For example: const [x = 10, y = 20] = [5];
will set x
to 5
and y
to 20
.
Are there any limitations I should be aware of?
One limitation is that default values only apply when the value is undefined
. If the property is present but has a value of null
, the default will not be used.
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