How do I use URL reversing in Django with parameters?

How do I use URL reversing in Django with parameters?

In Django, you can use the reverse() function to generate URLs from your view names and parameters. For example, if you have a URL pattern like path('article/<int:id>/', views.article_detail, name='article_detail'), you can reverse it by calling reverse('article_detail', args=[article_id]).

Can you show me an example of how to implement this in a view?

Sure! In your view, you can do something like this:

from django.urls import reverse
from django.http import HttpResponseRedirect

def my_view(request):
    article_id = 1  # Example article ID
    url = reverse('article_detail', args=[article_id])
    return HttpResponseRedirect(url)

What if I want to pass multiple parameters?

You can pass multiple parameters by including them in the args list. For example, if your URL pattern is path('article/<int:id>/<str:slug>/', views.article_detail, name='article_detail'), you can reverse it like this:

url = reverse('article_detail', args=[article_id, article_slug])

Is there a way to reverse URLs using keyword arguments?

Yes! You can use the kwargs argument in the reverse() function. For example:

url = reverse('article_detail', kwargs={'id': article_id, 'slug': article_slug})