How can I handle errors in Python generators?
You can handle errors in Python generators using try-except blocks within the generator function.
Can you give me an example of that?
Sure! Here's a simple example:
def my_generator():
try:
yield 1
yield 2
raise ValueError('An error occurred!')
except ValueError as e:
print(e)
yield 3
What happens if I don't handle the error?
If you don't handle the error, the generator will stop execution and raise the exception, which can crash your program.
Is there a way to resume the generator after an error?
Yes, you can use a loop to call the generator again after catching the error, allowing it to continue from the last yielded value.
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