How do I pass arrays to functions in C?
In C, you can pass an array to a function by passing the array's name. This gives the function access to the array's elements.
Can you show me an example of that?
Sure! Here's a simple example:
#include <stdio.h>
void printArray(int arr[], int size) {
for (int i = 0; i < size; i++) {
printf("%d ", arr[i]);
}
}
int main() {
int myArray[] = {1, 2, 3, 4, 5};
printArray(myArray, 5);
return 0;
}
This code defines a function printArray
that takes an array and its size as parameters.
What happens if I don't pass the size of the array?
If you don't pass the size, the function won't know how many elements to process, which can lead to undefined behavior or accessing out-of-bounds memory.
Is there a way to pass a multidimensional array?
Yes, you can pass a multidimensional array by specifying the dimensions in the function parameters. For example:
void print2DArray(int arr[][3], int rows) {
for (int i = 0; i < rows; i++) {
for (int j = 0; j < 3; j++) {
printf("%d ", arr[i][j]);
}
printf("\n");
}
}
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