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What is an LRU Cache and how is it implemented in different programming languages?

An example of an AI chatbot conversation about LRU Cache implementations in various programming languages.

😀
You

What is an LRU Cache and how does it work?

MagicBuddy
MagicBuddy

An LRU (Least Recently Used) Cache is a data structure that stores a limited number of items. When the cache reaches its limit, it removes the least recently used item to make space for new ones.

😀
You

Can you show me how to implement an LRU Cache in Python?

MagicBuddy
MagicBuddy

Sure! Here's a simple implementation using a dictionary and a doubly linked list:

class Node:
    def __init__(self, key, value):
        self.key = key
        self.value = value
        self.prev = None
        self.next = None

class LRUCache:
    def __init__(self, capacity: int):
        self.capacity = capacity
        self.cache = {}  # key -> Node
        self.head = Node(0, 0)  # dummy head
        self.tail = Node(0, 0)  # dummy tail
        self.head.next = self.tail
        self.tail.prev = self.head

    def _remove(self, node):
        prev_node = node.prev
        next_node = node.next
        prev_node.next = next_node
        next_node.prev = prev_node

    def _add(self, node):
        prev_node = self.tail.prev
        prev_node.next = node
        node.prev = prev_node
        node.next = self.tail
        self.tail.prev = node

    def get(self, key: int) -> int:
        if key in self.cache:
            node = self.cache[key]
            self._remove(node)
            self._add(node)
            return node.value
        return -1

    def put(self, key: int, value: int) -> None:
        if key in self.cache:
            self._remove(self.cache[key])
        node = Node(key, value)
        self.cache[key] = node
        self._add(node)
        if len(self.cache) > self.capacity:
            lru = self.head.next
            self._remove(lru)
            del self.cache[lru.key]
😀
You

How would this implementation differ in Java?

MagicBuddy
MagicBuddy

In Java, you can use a similar approach with a HashMap and a doubly linked list. Here's a basic outline:

class Node {
    int key, value;
    Node prev, next;
    Node(int key, int value) {
        this.key = key;
        this.value = value;
    }
}

class LRUCache {
    private Map<Integer, Node> cache;
    private Node head, tail;
    private int capacity;

    public LRUCache(int capacity) {
        this.capacity = capacity;
        cache = new HashMap<>();
        head = new Node(0, 0);
        tail = new Node(0, 0);
        head.next = tail;
        tail.prev = head;
    }

    private void remove(Node node) {
        node.prev.next = node.next;
        node.next.prev = node.prev;
    }

    private void add(Node node) {
        node.prev = tail.prev;
        node.next = tail;
        tail.prev.next = node;
        tail.prev = node;
    }

    public int get(int key) {
        if (cache.containsKey(key)) {
            Node node = cache.get(key);
            remove(node);
            add(node);
            return node.value;
        }
        return -1;
    }

    public void put(int key, int value) {
        if (cache.containsKey(key)) {
            remove(cache.get(key));
        }
        Node newNode = new Node(key, value);
        cache.put(key, newNode);
        add(newNode);
        if (cache.size() > capacity) {
            Node lru = head.next;
            remove(lru);
            cache.remove(lru.key);
        }
    }
}
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