Can you explain what an LRU Cache is?
An LRU Cache, or Least Recently Used Cache, is a data structure that stores a limited number of items and evicts the least recently used item when it reaches its capacity.
How can I implement an LRU Cache in Python?
In Python, you can use the collections.OrderedDict
to maintain the order of items. Here's a simple implementation:
from collections import OrderedDict
class LRUCache:
def __init__(self, capacity: int):
self.cache = OrderedDict()
self.capacity = capacity
def get(self, key: int) -> int:
if key not in self.cache:
return -1
else:
self.cache.move_to_end(key)
return self.cache[key]
def put(self, key: int, value: int) -> None:
if key in self.cache:
self.cache.move_to_end(key)
self.cache[key] = value
if len(self.cache) > self.capacity:
self.cache.popitem(last=False)
What about in Java?
In Java, you can use a combination of a HashMap and a doubly linked list. Here's a basic implementation:
import java.util.HashMap;
class LRUCache {
private class Node {
int key, value;
Node prev, next;
Node(int key, int value) { this.key = key; this.value = value; }
}
private HashMap<Integer, Node> map;
private Node head, tail;
private int capacity;
public LRUCache(int capacity) {
this.capacity = capacity;
map = new HashMap<>();
head = new Node(0, 0);
tail = new Node(0, 0);
head.next = tail;
tail.prev = head;
}
private void remove(Node node) {
node.prev.next = node.next;
node.next.prev = node.prev;
}
private void addToHead(Node node) {
node.next = head.next;
head.next.prev = node;
head.next = node;
node.prev = head;
}
public int get(int key) {
if (!map.containsKey(key)) return -1;
Node node = map.get(key);
remove(node);
addToHead(node);
return node.value;
}
public void put(int key, int value) {
if (map.containsKey(key)) {
Node node = map.get(key);
remove(node);
node.value = value;
addToHead(node);
} else {
if (map.size() == capacity) {
map.remove(tail.prev.key);
remove(tail.prev);
}
Node newNode = new Node(key, value);
map.put(key, newNode);
addToHead(newNode);
}
}
}
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