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What is LRU Cache and how is it implemented in different programming languages?

An example of an AI chatbot conversation about LRU Cache implementations in various programming languages.

😀
You

Can you explain what an LRU Cache is?

MagicBuddy
MagicBuddy

An LRU Cache, or Least Recently Used Cache, is a data structure that stores a limited number of items and evicts the least recently used item when it reaches its capacity.

😀
You

How can I implement an LRU Cache in Python?

MagicBuddy
MagicBuddy

In Python, you can use the collections.OrderedDict to maintain the order of items. Here's a simple implementation:

from collections import OrderedDict

class LRUCache:
    def __init__(self, capacity: int):
        self.cache = OrderedDict()
        self.capacity = capacity

    def get(self, key: int) -> int:
        if key not in self.cache:
            return -1
        else:
            self.cache.move_to_end(key)
            return self.cache[key]

    def put(self, key: int, value: int) -> None:
        if key in self.cache:
            self.cache.move_to_end(key)
        self.cache[key] = value
        if len(self.cache) > self.capacity:
            self.cache.popitem(last=False)
😀
You

What about in Java?

MagicBuddy
MagicBuddy

In Java, you can use a combination of a HashMap and a doubly linked list. Here's a basic implementation:

import java.util.HashMap;

class LRUCache {
    private class Node {
        int key, value;
        Node prev, next;
        Node(int key, int value) { this.key = key; this.value = value; }
    }

    private HashMap<Integer, Node> map;
    private Node head, tail;
    private int capacity;

    public LRUCache(int capacity) {
        this.capacity = capacity;
        map = new HashMap<>();
        head = new Node(0, 0);
        tail = new Node(0, 0);
        head.next = tail;
        tail.prev = head;
    }

    private void remove(Node node) {
        node.prev.next = node.next;
        node.next.prev = node.prev;
    }

    private void addToHead(Node node) {
        node.next = head.next;
        head.next.prev = node;
        head.next = node;
        node.prev = head;
    }

    public int get(int key) {
        if (!map.containsKey(key)) return -1;
        Node node = map.get(key);
        remove(node);
        addToHead(node);
        return node.value;
    }

    public void put(int key, int value) {
        if (map.containsKey(key)) {
            Node node = map.get(key);
            remove(node);
            node.value = value;
            addToHead(node);
        } else {
            if (map.size() == capacity) {
                map.remove(tail.prev.key);
                remove(tail.prev);
            }
            Node newNode = new Node(key, value);
            map.put(key, newNode);
            addToHead(newNode);
        }
    }
}
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