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How can I solve the N-Queens problem in different programming languages?

An example of an AI chatbot conversation about solving the N-Queens problem in various programming languages.

😀
You

How can I solve the N-Queens problem in different programming languages?

MagicBuddy
MagicBuddy

The N-Queens problem involves placing N queens on an N×N chessboard so that no two queens threaten each other. Would you like to see examples in specific languages?

😀
You

Yes, can you show me how to implement it in Python?

MagicBuddy
MagicBuddy

Sure! Here's a simple backtracking solution in Python:

def solve_n_queens(n):
    def is_safe(board, row, col):
        for i in range(col):
            if board[row][i] == 1:
                return False
        for i, j in zip(range(row, -1, -1), range(col, -1, -1)):
            if board[i][j] == 1:
                return False
        for i, j in zip(range(row, n, 1), range(col, -1, -1)):
            if board[i][j] == 1:
                return False
        return True

    def solve(board, col):
        if col >= n:
            return True
        for i in range(n):
            if is_safe(board, i, col):
                board[i][col] = 1
                if solve(board, col + 1):
                    return True
                board[i][col] = 0
        return False

    board = [[0] * n for _ in range(n)]
    if not solve(board, 0):
        return []
    return board

This code defines a function to solve the N-Queens problem using backtracking.

😀
You

That's great! Can you provide an example in Java as well?

MagicBuddy
MagicBuddy

Absolutely! Here's a Java implementation of the N-Queens problem:

public class NQueens {
    public static void solveNQueens(int n) {
        int[] board = new int[n];
        solve(board, 0);
    }

    private static void solve(int[] board, int row) {
        if (row == board.length) {
            printSolution(board);
            return;
        }
        for (int col = 0; col < board.length; col++) {
            if (isSafe(board, row, col)) {
                board[row] = col;
                solve(board, row + 1);
            }
        }
    }

    private static boolean isSafe(int[] board, int row, int col) {
        for (int i = 0; i < row; i++) {
            if (board[i] == col || 
                board[i] - i == col - row || 
                board[i] + i == col + row) {
                return false;
            }
        }
        return true;
    }

    private static void printSolution(int[] board) {
        for (int i = 0; i < board.length; i++) {
            for (int j = 0; j < board.length; j++) {
                if (board[i] == j) {
                    System.out.print("Q ");
                } else {
                    System.out.print(". ");
                }
            }
            System.out.println();
        }
        System.out.println();
    }
}

This code uses recursion to place queens on the board and checks for safety.

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