How can I solve the N-Queens problem using different programming languages?
You can solve the N-Queens problem using various programming languages like Python, Java, and C++. Would you like examples in a specific language?
Yes, please show me how to do it in Python.
Sure! Here's a simple backtracking solution in Python:
def solve_n_queens(n):
def is_safe(board, row, col):
for i in range(col):
if board[row][i] == 1:
return False
for i, j in zip(range(row, -1, -1), range(col, -1, -1)):
if board[i][j] == 1:
return False
for i, j in zip(range(row, n, 1), range(col, -1, -1)):
if board[i][j] == 1:
return False
return True
def solve_util(board, col):
if col >= n:
return True
for i in range(n):
if is_safe(board, i, col):
board[i][col] = 1
if solve_util(board, col + 1):
return True
board[i][col] = 0
return False
board = [[0] * n for _ in range(n)]
if not solve_util(board, 0):
return "No solution exists"
return board
print(solve_n_queens(4))
That's great! Can you provide a Java example as well?
Absolutely! Here's a Java implementation of the N-Queens problem:
public class NQueens {
static int N = 4;
static boolean isSafe(int board[][], int row, int col) {
for (int i = 0; i < col; i++)
if (board[row][i] == 1)
return false;
for (int i = row, j = col; i >= 0 && j >= 0; i--, j--)
if (board[i][j] == 1)
return false;
for (int i = row, j = col; j >= 0 && i < N; i++, j--)
if (board[i][j] == 1)
return false;
return true;
}
static boolean solveNQUtil(int board[][], int col) {
if (col >= N)
return true;
for (int i = 0; i < N; i++) {
if (isSafe(board, i, col)) {
board[i][col] = 1;
if (solveNQUtil(board, col + 1))
return true;
board[i][col] = 0;
}
}
return false;
}
static void solveNQ() {
int board[][] = new int[N][N];
if (!solveNQUtil(board, 0)) {
System.out.print("Solution does not exist");
return;
}
printSolution(board);
}
static void printSolution(int board[][]) {
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++)
System.out.print(" " + board[i][j] + " ");
System.out.println();
}
}
public static void main(String args[]) {
solveNQ();
}
}
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