How do I pass arguments to shell scripts?
You can pass arguments to a shell script by including them after the script name in the command line.
Can you give me an example?
Sure! If your script is named script.sh
, you can run it like this: ./script.sh arg1 arg2
.
How do I access those arguments inside the script?
Inside the script, you can access the arguments using $1
, $2
, etc. For example, $1
refers to arg1
.
What if I want to pass a variable number of arguments?
You can use a loop to iterate over all arguments with for arg in "$@"; do ... done
.
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