What is the time complexity of DFS and BFS?
The time complexity of Depth-First Search (DFS) and Breadth-First Search (BFS) is O(V + E), where V is the number of vertices and E is the number of edges.
Can you explain why it's O(V + E)? I don't quite understand.
Sure! In both algorithms, every vertex is visited once, contributing O(V), and every edge is explored once, contributing O(E). Thus, the total is O(V + E).
Are there any scenarios where one is better than the other?
Yes, DFS is better for scenarios requiring deep exploration, while BFS is better for finding the shortest path in unweighted graphs.
What about their space complexity?
The space complexity for DFS is O(h) where h is the maximum depth of the tree, while BFS has a space complexity of O(w) where w is the maximum width of the tree.
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