Can you explain the time complexity of Depth First Search?
Sure! The time complexity of Depth First Search (DFS) is O(V + E), where V is the number of vertices and E is the number of edges.
What do V and E represent in this context?
In this context, V represents the number of vertices (or nodes) in the graph, and E represents the number of edges connecting those vertices.
Why is it O(V + E) and not just O(V)?
It's O(V + E) because DFS needs to explore all vertices and all edges in the graph to ensure it visits every node.
Can you give an example of how DFS works?
Certainly! Imagine a graph with nodes A, B, C, and edges connecting them. DFS starts at A, explores B, then C, visiting each node until all are explored.
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