What is the time complexity of BFS?
The time complexity of Breadth-First Search (BFS) is O(V + E), where V is the number of vertices and E is the number of edges.
Can you explain why it's O(V + E)?
Sure! BFS explores each vertex and edge once. It visits all vertices (V) and traverses all edges (E) in the graph.
What about the space complexity?
The space complexity of BFS is O(V) because it needs to store all the vertices in the queue.
Is BFS better than DFS in any scenario?
Yes, BFS is better for finding the shortest path in unweighted graphs, while DFS can be more memory efficient in some cases.
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