What is the time and space complexity of Breadth-First Search (BFS)?
The time complexity of BFS is O(V + E), where V is the number of vertices and E is the number of edges. The space complexity is O(V) due to the storage of the queue.
Can you explain why the time complexity is O(V + E)? I don't quite understand.
Sure! In BFS, each vertex is processed once, contributing O(V), and each edge is examined once, contributing O(E). Thus, the total is O(V + E).
What about the space complexity? Why is it O(V)?
The space complexity is O(V) because, in the worst case, we need to store all vertices in the queue at once, especially in a complete graph.
Are there any scenarios where BFS is preferred over DFS?
Yes, BFS is preferred when you need the shortest path in an unweighted graph or when exploring all neighbors at the present depth before moving on.
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