How do I solve quadratic equations?
To solve a quadratic equation, you can use the quadratic formula: x = (-b ± √(b² - 4ac)) / 2a.
Can you give me an example using the equation 2x² + 3x - 5 = 0?
Sure! Here, a = 2, b = 3, and c = -5. Plugging into the formula gives x = (-3 ± √(3² - 42(-5))) / (2*2).
What do I get when I calculate that?
Calculating it gives you x = 1 and x = -2.5 as the solutions.
What if the equation has no real solutions?
If the discriminant (b² - 4ac) is less than zero, the equation has no real solutions, only complex ones.
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